Y X2 4X 2. To solve the equation factor x^ {2}4x+4 using formula x^ {2}+\left (a+b\right)x+ab=\left (x+a\right)\left (x+b\right) To find a and b set up a system to be solved Since ab is positive a and b have the same sign Since a+b is negative a and b are both negative List all such integer pairs that give product 4.
The equation is now solved x^ {2}4x+4=y Swap sides so that all variable terms are on the left hand side \left (x2\right)^ {2}=y Factor x^ {2}4x+4 In general when x^ {2}+bx+c is a perfect square it can always be factored as \left (x+\frac {b} {2}\right)^ {2} \sqrt {\left (x2\right)^ {2}}=\sqrt {y}.
Graph y=x^24×2 Mathway
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Solve x^24x+4=0 Microsoft Math Solver
y = x2 − 4x − 2 y = x 2 4 x 2 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for x 2 − 4 x − 2 x 2 4 x 2 Tap for more steps Use the form a x 2 + b x + c a x 2 + b x + c to find the values of a a b b and c c.
Quadratic Function
Selesaikan y=x^24x+2 Microsoft Math Solver
How do you write y=x^24x+2 into vertex form? Socratic
Solve y=x^24x+4 Microsoft Math Solver
y = a(x − h)2 + k where (hk) is the vertex of the parabola We can use the process of Completing the Square to get this into the Vertex Form y = x2 − 4x +2 → y −2 = x2 − 4x (Transposed 2 to the Left Hand Side) Now we ADD 4 from each side to complete the square → y −2 +4 = x2 − 4x +22 → y +2 = (x − 2)2 → y = 1 ⋅ (x −2)2 −2 is the Vertex Form.